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0.07x-0.6x^2=-1
We move all terms to the left:
0.07x-0.6x^2-(-1)=0
We add all the numbers together, and all the variables
-0.6x^2+0.07x+1=0
a = -0.6; b = 0.07; c = +1;
Δ = b2-4ac
Δ = 0.072-4·(-0.6)·1
Δ = 2.4049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.07)-\sqrt{2.4049}}{2*-0.6}=\frac{-0.07-\sqrt{2.4049}}{-1.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.07)+\sqrt{2.4049}}{2*-0.6}=\frac{-0.07+\sqrt{2.4049}}{-1.2} $
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